Question

differentiate
d/dx × (x + cosx)/tanx​

Answer 1

Answer:

Let u = ( x + cosx ) and v= tanx. By using the quotient rule,

d/dx = [tanx(x+ cosx/dx) - (x+cosx)(tanx/dx)] / (tanx²)

= [tanx(1-sinx) - (x+cosx) sec²x] / (tanx²)

= [tanx - tanx . sinx - xsec²x -secx] / (tanx²)

since this cannot be further reduced to any form, we stop here. This is the answer!

HOPE THIS HELPS!! Good luck