Math, asked by jameela55, 1 year ago

Differentiate e^2x log sin 3x differentiate with respect to x

Answers

Answered by beautyandbrains
1

e^2x log sin 3x

= 2e^2x * 1/sin 3x * 3 cos 3x

Hope this helped please mark as brainliest

Answered by Anonymous
9

Heya!!

Given Function is

F(x) = e^2x log (Sin 3x)

Differentiate both sides w.r.t x we have

F'(x) = e^2x d(log (Sin 3x)/dx + d(e^2x)/dx log (Sin 3x)

F'(x) = 3e^2x Cos 3x/Sin 3x + 2e^2x log (Sin 3x)

F'(x) = e^2x { 3Cot 3x + 2 log ( Sin 3x ) }


jameela55: thankuuuuu
Ritiksuglan: hiii
Similar questions