Question

differentiate : e^x/sec x with respect to x.​

Answer 1

$y = \frac{e {}^{x} }{ sec \: x }$

$\frac{dy}{dx} = \frac{VU {}^{1} - UV {}^{1} }{V {}^{2} }$

$\frac{dy}{dx} = \frac{ \sec \: x. \frac{d(e {}^{x}) }{dx} - e {}^{x} . \frac{d( \sec \: x) }{dx} }{( sec \: x {})^{2} }$

$\frac{dy}{dx} = \frac{ \sec x.e {}^{x} - \: e {}^{x.} \sec x. \tan \: x }{( \sec \: x \: {})^{2} }$

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