Question

differentiate f(x) = 3-x/3+4x with respect to x by first principle.​

Answer 1

Answer:

f'(x) = -15/((3+4x)^2)

Step-by-step explanation:

d(u/v)/dx = (v*(d/dx(u))-u*(d/dx(v)))/(v^2)

f'(x) = ((3+4x)(-1)-(3-x)(4))/((3+4x)^2)

= (-3-4x-12+4x)/((3+4x)^2)

= -15/((3+4x)^2)