Question

differentiate
F(X) Sin loge^x

please do explain in details.

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Answer 1

Explanation:

let y= f(x) = sin log e^x

dy/dx = cos (loge^x) ×[(e^x)/(e^x) ]

= cos(log e^x) (1)

= cos(x)

since log and exponential are opp like × and÷ so that they are cancelled

Alter

let y= f(x) = sin log e^x

y = sin(x)

dy/dx = cosx