Differentiate f(x) = x^2 + 2x using firts principle of derivates.
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Answer:
First Principle of Finding Derivative:
f′(x)=limh→0f(x+h)−f(x)h
We need to find f′(x) , given that f(x)=2x2−x .
Which means that f(x+h)=2(x+h)2−(x+h)
f′(x)=limh→0(2(x+h)2−(x+h))−(2x2−x)h
Expand into standard polynomial form and simplify.
f′(x)=limh→0(2(x2+2x h+h2)−x−h)−2x2+xh
f′(x)=limh→0(2x2+4x h+2h2−x−h)−2x2+xh
f′(x)=limh→02x2+4x h+2h2−x−h−2x2+xh
f′(x)=limh→04x h+2h2−hh
Factor
f′(x)=limh→0h(4x+2h−1)h
Cancel
f′(x)=limh→0[4x+2h−1]
Direct substitution
f′(x)=4x+2(0)−1
f′(x)=4x−1 → this is your answer
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