Differentiate f(x) = x3+x2+x-1/x^1/2
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Answer:
Let the two prime numbers be 3 and 5.
Multiples of 3 and 5 are as follows
3 ... 3, 6, 9, 12, 15, 18,....
5 ... 5, 10, 15, 20, ....
LCM(3, 5) = 15
Since 3 and 5 are prime numbers.
HCF(3, 5) = 1
LCM(3, 5) × HCF(3, 5) = 15 × 1 = 15 ... (ii)
3 × 5 = 15 ...(iii)
From (ii) and (iii), we can say that
The product of any two prime number is equal to the product of their HCF and LCM.
Explanation:
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Explanation:
Differentiate f(x) = x3+x2+x-1/x^1/2 =
x3+x2+ x^1/2 - 1/x^1/2
F'(x) = 3x² + 2x + 1/2 × x^-1/2 +1/2 ×1/x^3/2
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