Question

differentiate from first principles
(x - 1)²​

Answer 1

) (x−1)

2

f

′

(x)=

x→0

+

h

x+h)−f(x)

=

h→0

lim

+

h

(x+h−1)

2

−(x−1)

2

=

h→0

lim

+

h

x+h−1+x−1)(x+h−1−x+1)

=

h→0

lim

+

h

(2x−2+h)(h)

$)  (x−1)2</p><p>f′(x)=x→0+hx+h)−f(x)</p><p></p><p>=h→0lim+h(x+h−1)2−(x−1)2</p><p></p><p>=h→0lim+hx+h−1+x−1)(x+h−1−x+1)</p><p></p><p>=h→0lim+h(2x−2+h)(h)</p><p></p><p>=2(x−</p><p></p><p>$

=2(x−

Answer 2

Answer:

2x

Step-by-step explanation:

(x-1)²=x²-1²

=x²-1

to differentiate X²-1

=2x