differentiate it fast
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df(t)/dt = t + 4/t
Differentiating this again with respect to t
We get,
d^2f(t)/dt^2= d(t)/dt + 4d(1/t)/dt
Therefore,
d^2 f(t)/dt^2 = 1 - 4/t^2 ....(using d(x^n) / dx = n*x^n-1
Differentiating this again with respect to t
We get,
d^2f(t)/dt^2= d(t)/dt + 4d(1/t)/dt
Therefore,
d^2 f(t)/dt^2 = 1 - 4/t^2 ....(using d(x^n) / dx = n*x^n-1
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