Math, asked by akbgrtdf, 6 months ago

differentiate log(x^2-4x+3)

Answers

Answered by biligiri

1

Step-by-step explanation:

y = log (x² - 4x + 3)

dy/dx = 1/(x² - 4x + 3) * (2x - 4) [ chain rule ]

=> y' = (2x - 4) / (x² - 4x + 3)

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