differentiate log(x^2-4x+3)
Answers
Answered by
1
Step-by-step explanation:
y = log (x² - 4x + 3)
dy/dx = 1/(x² - 4x + 3) * (2x - 4) [ chain rule ]
=> y' = (2x - 4) / (x² - 4x + 3)
Similar questions
English,
3 months ago
Business Studies,
3 months ago
Biology,
6 months ago
Computer Science,
10 months ago
English,
10 months ago
Science,
10 months ago