Question

Differentiate

(log x)x + x x cos x​

Answer 1

Answer:

Let y = (x cos x)x + (x sin x)1/x Also, let u = (x cos x)x and v = (x sin x)1/x y = u + v dy/dx = du/dx + dv/dx ...(1) u = (x cos x)x log u = log (x cos ...

Answer 2

Answer:

y=(cosx) x

By Taking log on Both Side

logy=xlogcosxy1dxdy

=logcosx−xtanx dxdy

=(cosx) x [logcosx−xtanx]