Question

differentiate log² sin x​

Answer 1

Answer:

(2cosxlog(sinx))/sinx

Step-by-step explanation:

by using chain rule

1) differentiate power term we get 2log(sinx)

2)differentiate log term we get 1/sinx

3) differentiating the sin term we get cosx

4) multiply both answers we get

2log(sinx)×(1/sinx)×cosx={2cosxlog(sinx)}/sinx

therefore the answer