differentiate log² sin x
Answers
Answered by
0
Answer:
(2cosxlog(sinx))/sinx
Step-by-step explanation:
by using chain rule
1) differentiate power term we get 2log(sinx)
2)differentiate log term we get 1/sinx
3) differentiating the sin term we get cosx
4) multiply both answers we get
2log(sinx)×(1/sinx)×cosx={2cosxlog(sinx)}/sinx
therefore the answer
Similar questions