differentiate( log3/logx)
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1
Answer:
By Change of Base Formula:
log
b
x
=
log
a
x
log
a
b
,
y
=
log
3
x
=
ln
x
ln
3
By taking the derivative,
y
'
=
1
x
ln
3
=
1
(
ln
3
)
x
Step-by-step explanation:
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