Math, asked by aarush29, 1 year ago

Differentiate logx^x with respect to x

Answers

Answered by saurabhthakur56

d/dx logx^x
=d/dx (xlogx)
by product rule
=xd/dx logx+logxd/dx x
=x (1/x)+logx×1
=1+logx

aarush29: bhai d/dx (x) =1 hota h

aarush29: Apne 0 kyu kiya

saurabhthakur56: are bhai typing me glti hogi sorry yrr

aarush29: it's ok but thanks for the help

saurabhthakur56: welcm bhai

Answered by Aadarshini6A1

Answer:

y=(logx) x

Taking log on both sides, we get,

logy=xlog(logx)

Differentiating w.r.t x, we get,

y1dxdy=logxx×x1+log(logx)

dxdy=(logx)x(logx1+log(logx))

Step-by-step explanation:

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