differentiate of sin square x ÷1+cos square x
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Answer:
we are you still have the same to you so much
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Explanation:
You can always compute the derivative using the quotient rule, but here a simpler approach is possible.
Let's use the identity
sin2x+cos2x=1⇔sin2x=1−cos2x
and the rule
a2−b2=(a+b)(a−b)
to simplify your function:
f(x)=sin2x1−cosx=1−cos2x1−cosx=(1−cosx)(1+cosx)1−cosx
×=(1−cosx)(1+cosx)(1−cosx)=1+cosx
Now, it's much easier to compute the derivative!
f'(x)=−sin(x)
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