Question

differentiate r= (1 + sec theta )sin theta​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\tt{r=(1+sec(\theta))\,sin(\theta)}$

$\tt{\implies\,r=sin(\theta)+sec(\theta)\cdot\,sin(\theta)}$

$\tt{\implies\,r=sin(\theta)+\dfrac{1}{cos(\theta)}\cdot\,sin(\theta)}$

$\tt{\implies\,r=sin(\theta)+tan(\theta)}$

$\tt{\implies\,\dfrac{dr}{d\theta}=cos(\theta)+sec^2(\theta)}$