Differentiate sec-1
1
2x2-1
with respect to
√1-x²
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Answer:
saorry dont know the answer
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Step-by-step explanation:
let sec -1 (1/2xsquare- 1)=4
u= cos -1 (2xsquare-1)
X=cos tera
u= cos-1(2cos square teta-1)
u=cos-1( cos2 teta)
u= 2 teta
but teta= cos-1 X
du/DX= -1 / root 1-x square
let v =root 1-x square
DV/ DX= 1/2 root 1- * X -2x=- X/ root 1- X square
using du/ DX /DV/DX= -1/root 1- X square/-X / root 1-x = 1/x
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