Question

Differentiate sec inverse (1/root over 1-x square)​

Answer 1

Answer:

Reffer above the attachment

Answer 2

Step-by-step explanation:

Given , sec−11+x2+cosec−1(y1+y2)+cot−1(z1)=π

⇒tan−1x+tan−1y+tan−1z=π

⇒tan−1(1−xy−yz−zxx+y+z−xyz)=π=tan−1(0)

⇒x+y+z−xyz=0

⇒x+y+z=xyz