Question

Differentiate sec(tan√x)​

Answer 1

$y = sec(tan \sqrt{x} ) \\ \\ \frac{dy}{dx} = sec(tan \sqrt{x} )tan(tan \sqrt{x} ) \frac{d}{dx} tan \sqrt{x} \\ \\ \frac{dy}{dx} = sec(tan \sqrt{x} )tan(tan \sqrt{x} ) {sec}^{2} \sqrt{x} \frac{d}{dx} \sqrt{x} \\ \\ \frac{dy}{dx} = sec(tan \sqrt{x} )tan(tan \sqrt{x} ) {sec}^{2} \sqrt{x} \frac{1}{2 \sqrt{x} }$