Math, asked by Kimpower, 10 months ago

Differentiate sec²x + csc²y =4

Answers

Answered by Anonymous
4

 \frac{d}{dx} ( {sec}^{2} x) +  \frac{d}{dx} ( {cosec}^{2} x) =  \frac{d}{dx} (4) \\

2secx \frac{d}{dx} (secx) + 2cosecx \frac{d}{dx} (cosecx) = 0

2secx \: secxtanx \:  + 2cosecx \: cotx

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