Question

differentiate sin ^-1 (3x-4x^3) when 1/2<x<1​

Answer 1

Step-by-step explanation:

sin‐¹ ( 3x - 4x³)

let x = sin○

sin‐¹( 3 sin○ - 4 sin³○)

sin‐¹ sin3○

3○

now , ○ = sin‐¹x

d 3○ d 3 sin‐¹x

____ = ________

dx dx

3

=________

root ( 1 - x²)