Question

differentiate sin^2x + cos^2y = 1

Answer 1

solution:- let y = sin²x + cos²x

dy/dx = d(sin²x+ cos²x)/dx = d(1)/dx

=> using chain rule f'(x) = F'(g(x) (g'(x))

•°• 2sinx*cosx + 2cosxy(-siny)dy/dx = 0

=> 2sinx*cosx - 2siny*cosy dy/dx= 0:

=> 2sinx*cosx = 2siny*cosy dy/dx

=> dy/dx = sinx*cosx/siny*cosy Answer

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Answer 2

Answer:

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Step-by-step explanation:

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