Question

differentiate sin 3x with respect to cos 3x​

Answer 1

Step-by-step explanation:

here tita = 3x

sin 3x = 1/ cos 3x

Answer 2

Answer:

- tan x

Step-by-step explanation:

let u =sin 3x

and v =cos 3x

du/dx = -3 sin 2x cosx,

dv/dx = 3 cos 2x sinx.

now , du/dv = -3 sin 2x cosx/ 3 cos 2x sinx

= -sinx/cosx

= -tanx