Question

Differentiate
sin (ax+b)​

Answer 1

Step-by-step explanation:

Let y =(ax + b) and z = sin(ax + b)

to formula, d(sinx)/dx=cosx

d(ax+b)/dx=d(ax)/dx+d(b)/dx

= a+0=a

According to chain rule of differentiation,

dz/dx=dz/dy×dy/dx

= cos(ax+b)×a

= acos(ax+b)