differentiate sin(cos^2 (√x))
Answers
Answered by
1
Answer:
−2x⋅sinx
2
⋅cos(cosx
2
)
Step-by-step explanation:
Let y =sin(cosx
2
)
Differentiate both side with respect to x.
dx
dy
=
dx
d{sincosx
2
}
= cos(cosx
2
)
dx
d
(cosx
2
)
= cos(cosx
2
)(−sinx
2
)
dx
d
(x
2
)
= cos(cosx
2
)(−sinx
2
)2x
= −2x⋅sinx
2
⋅cos(cosx
2
)
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Answered by
1
Step-by-step explanation:
f(f(x))=
cf(x)+d
af(x)+b
f(f(x))=
c
cx+d
ax+b
+d
a
cx+d
ax+b
+b
f(f(x))=
acx+bc+d
2
+dcx
a
2
x+ab+bcx+bd
=x
⇒a
2
x+ab+bcx+bd=acx
2
+bcx+d
2
x+dcx
2
Given a=−d, the above equation can also be verified
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