Question

differentiate sin cube x with respect to cos cube x

Answer 1

Hey!!!

Here is your answer_____________

let u = sin^3 and v = cos^3

differentiate u and v with respect to x,

we get,

du/dv = (3sin^2) * d/dx(sinx)

=(3sin^2)(cosx) --------(1)

and

dv/dx = (3cos^2)*d/dx(cosx)

=(3cos^2)(-sinx) ---------(2)

since given differentiate sin^3 with respect to cos^3

therefore divide equation (1) by (2)

we get,

du/dv = [(3sin^2)(cosx)]/[-(3cos^2)(sinx)

= -tan^2*cotx

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HOPE THIS ANSWER WILL HELP U......

Answer 2

Coconeha09 has given the correct answer...