Differentiate sin inverse sinx+cosx / root 2.
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let (a) represent sqrt(2)
you can write sinx+cosx/a=sinxcos(pi/4)+cosxcos(pi/4)=...
now you can differentiate it normally
keeping in mind the readjustment of range as we do in case of inverse functions
you can write sinx+cosx/a=sinxcos(pi/4)+cosxcos(pi/4)=...
now you can differentiate it normally
keeping in mind the readjustment of range as we do in case of inverse functions
hshahahvau2ygvwy:
but the answer is not same
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