Differentiate sin(logx) with respect to x
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Answer:
Differentiation of sin x is cos x and using chain rule we can also find the differentiation of log X whose differentiation is 1/x. Again on differentiating X we have 1. So in this way we have to find the differentiation of an angle based equation. The steps are as follows :
Step-by-step explanation:
d(sin(logx))/dx =
= cos(logx).d(logx)/dx
=(1/x).cos(logx).d(x)/dx
=(1/x).cos(logx).1
=(1/x).cos(logx)
Hence the answer is before you.
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