Question

differentiate sin(x^2) w r t e^sinx​

Answer 1

Answer:

Applying chain rule,

dx

d

[sin(sinx

2

)]

=cos(sinx

2

)

dx

d

[sinx

2

]

=cos(sinx

2

).cosx

2

.

dx

d

(x

2

)

=2xcos(sinx

2

).cosx

2