Question

differentiate sin(x2 + x) wrt x.
​

Answer 1

Step-by-step explanation:

d(sin(x2+x))

We know that

dxdf(g(x))=f′(g(x))×g′(x)

⇒dxd(sin(x2+x))=cos(x2+x)×dxd(x2+x)

                         =cos(x2+x)×[dxdx2+dxdx]

                         =cos(x2+x)×[2x+1]

∴dxd(sin(x2+x))=(2x+1)cos(x2+x)