Question

Differentiate sin²x w.r.t ^

​

Answer 1

Step-by-step explanation:

$= \frac{d}{dx} ( \sin^{2}x ) \\ = 2 \sin(x) \frac{d}{dx} \sin(x) \\ = 2 \sin(x) \cos(x) = \sin(2x)$

Answer 2

Answer:

Let P=sinx ...(1)

Q=e

cosx

...(2)

On differentiating eq.(1) w.r.t. we get

dx

dp

=

dx

d

(sin

2

x)=2sinxcosx ...(3)

On differentiating eq.(2) w.r.t we get

dx

dθ

=

dx

d

(e

cosx)

=−e

cosx

sinx ...(4)

dividing eq.(3) and (4)

dx

dθ

dx

dp

=

−e

cosx

sinx

2sinxcosx

=

e

cosx

−2cosx

⎣

⎢

⎢

⎡

dx

dθ

dx

dp

=

e

cosx

−2cosx

⎦

⎥

⎥

⎤