Question

differentiate sinx/1+cosx​

Answer 1

u/v method :

[(1+cosx)(sinx)’ - (sinx)(1+cosx)’] / (1+cosx)^2

[(1+cosx)(cosx) - (sinx)(-sinx)] / (1+cosx)^2

[Cosx + cos^2(x) + sin^2(x)] / (1+cosx)^2

[1+cosx] / (1+cosx)^2 [As sin^2(x) + cos^2(x) = 1]

Therefore, ans = 1/(1+cosx).

Answer 2

I would use the Quotient Rule to get: enter image source here.