Question

differentiate sinx with respect to cosx

Answer 1

Bonjour!

$= > \frac{d \: sinx}{d \: cosx} \\ \\ = > \frac{ \frac{d \: sinx}{dx} }{ \frac{d \: cosx}{dx} } \\ \\ = > \frac{cos \: x}{ - sin \: x} \\ \\ = > - cotx$
Note:-

$\frac{d \: sinx}{dx} = cosx \\ \\ \frac{d \: cosx}{dx} = - sinx$


Hope this helps...:)

Answer 2

Hope it will helps u
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