Question

differentiate sinx³

Answer 1

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Answer 2

♪ Differentiation Using Chain Rule

$let \: y = \sin(x)^{3}$
$differentiating \: with \: respect \: to \: x \: on \: both \: sides$
$\frac{dy}{dx} \: = \frac{d(sinx^{3}) }{dx} \\ \frac{dy}{dx} \: = cosx^{3} \times \frac{dx^{3} }{dx} \: \\ = > cosx^{3} \times 3x^{2}$

Formulas Used :-
$1) \: \: \: \: \: \frac{d( \sin(x)) }{dx} \: = \cos(x) \\ 2) \: \: \: \: \: \frac{d {x}^{n} }{dx} = n {x}^{n - 1}$