differentiate tan-1[1+sinx/cosx] w.r.t x
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Step-by-step explanation:
qAnswer:
Tan^-1 ( sin x / 1 + cos x)
= Tan^-1 ( 2 sin x/2 cos x/2 / 2 cos^2 x/2 )
= Tan^-1 ( sin x/2 / cos x/2 )
= Tan^-1 ( tan x/2 )
= X/2.
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