Question

differentiate
Tan^-1(2x/1+15x^2)

Answer 1

Answer:

Step-by-step explanation:

Given Differentiate  

Tan^-1(2x/1+15x^2)

Let y = tan^-1 (2 x / 1 + 15 x^2)

We can write as tan^-1 (5 x – 3 x / 1 + 5 x. 3 x)

Let 5 x = tan A and 3 x = tan B

Now y = tan^-1 (tan A – tan B / 1 + tan A. tan B)

  y = tan^-1 [tan(A – B)]

 y = A – B

 y = tan^-1 5 x – tan^-1 3 x

So dy/dx = 1/1 + 25 x^2 x 5 – 1/1 + 9 x^2  x 3

Now dy/dx = 5/1 + 25 x^2 – 3/1 + 9 x^2