differentiate tan^-1(2x^2+3x+5)
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Answer: 4x+3/4x^4+12x^3+29x^2+30x+26
Step-by-step explanation:
f(x)=tan^-1(2x^2+3x+5)
Differentiation of tan^-1 x = 1/1+x^2
Differentiating f(x) we get-
=(1/1+(2x^2+3x+5)^2) × (4x+3) [By chain rule we multiply 4x+3]
=4x+3/1+4x^4+12x^3+29x^2+30x+25
=4x+3/4x^4+12x^3+29x^2+30x+26
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