Question

differentiate tan(cot x^1/2)​

Answer 1

Answer:

$\frac{ { \sec }^{2}( \sqrt{ cotx} ) ( - {cosec}^{2}x) }{2 \sqrt{ cotx} }$

Step-by-step explanation:

$tan( \sqrt{cotx} )$

$= \frac{d}{dx} tan( \sqrt{cotx} )$

$= { { \sec }^{2} (\sqrt{ cot x } }) \times \frac{1}{2 \sqrt{ cot x } } \times ( - {cosec}^{2}x)$

$= \frac{ { \sec }^{2}( \sqrt{ cotx} )( - {cosec}^{2} x) }{2 \sqrt{ cotx} }$