Question

Differentiate
${e}^{x} + 3 log(x)$
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Answer 1

Hii its tom85

your question

e^x + 3logx

solution

let y= e^x+ logx^3

differentiating with respect to X we get

dy/dx=e^x+3x/x

dy/dx=e^x+3

on differentiating

de^x/dx = e^x

d(logx)/dx=1/x

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hope it helps you dude