Question

differentiate
$\frac{1}{4x - 3}$
​

Answer 1

$\frac{1}{4x - 3} \\ = \frac{1}{4x - 3} \times \frac{4x + 3}{4x + 3} \\ = \frac{4x + 3}{(4x)^{2} - (3) ^{2} } \\ = \frac{4x + 3}{16x ^{2} - 9}$

Answer 2

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