Math, asked by tmsssssss, 9 months ago

differentiate
 log( \sqrt{1 -  \cos(3x )  \div1 +  \cos(3x) }

Answers

Answered by Itzraisingstar
2

Answer:

Step-by-step explanation:

⇒log√1-cos(3x)/1+cos(3x),

⇒y=log(2sin²3x)/2cos²3x),

⇒y=log(√tan²3x)=log(tan3x),

⇒dy/dx=1/tan3x  sec²3x . 3,

⇒dy/dx=3(sec²3x/tan 3),

⇒dy/dx=3/4  (1/cos²3x)/(sin3x/cos 3x),

⇒3/4 . 1/(sin3x.cos3x),

⇒dy/dx=3/4 . sec3x . cosec3x is the answer.

If wrong answer sorry i tried my level best to answer.

HOPE IT HELPS YOU.

Answered by ashishghosalkar4
1

Step-by-step explanation:

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