differentiate
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2
Answer:
Step-by-step explanation:
⇒log√1-cos(3x)/1+cos(3x),
⇒y=log(2sin²3x)/2cos²3x),
⇒y=log(√tan²3x)=log(tan3x),
⇒dy/dx=1/tan3x sec²3x . 3,
⇒dy/dx=3(sec²3x/tan 3),
⇒dy/dx=3/4 (1/cos²3x)/(sin3x/cos 3x),
⇒3/4 . 1/(sin3x.cos3x),
⇒dy/dx=3/4 . sec3x . cosec3x is the answer.
If wrong answer sorry i tried my level best to answer.
HOPE IT HELPS YOU.
Answered by
1
Step-by-step explanation:
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