Question

differentiate :
$\sqrt{log \: x } \: with \: respect \: to \: x$
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Answer 1

Step-by-step explanation:

$y = \sqrt{logx} \\ \\ \frac{dy}{dx} = \frac{1}{2} ({log})^{ \frac{3}{2} } \: \: \frac{d}{dx} (logx) \\ \\ \: \: \: \: \: \: = \frac{1}{2} (logx) ^{ \frac{3}{2} } \frac{1}{x} \\ \\ \: \: \: \: \: \ = \frac{1}{2x} {log}^{ \frac{3}{2} }$