Question

differentiate
${tan{x + 1}$


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Answer 1

Answer:

d/dx tan (x+1)

=sec^2 (x+1) d/dx (x+1)

=sec^2 (x+1)

Answer 2

hey mate

find here

d/d[(tan(x+1)]=?

now,

by using chain formula

d/dx[tan(x+1)]=sec^2(x+1)[d/dx(x+1)]

=sec^2(x+1)× 1

=sec^2(x+1)

using formula :

d/dx(tan x)=sec^2x.

i hope it's helps u.

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