Question

differentiate:
$y = log \: 3 {x}^{2}$






​

Answer 1

Answer:

y=log(3x

2

+2x+1)

⇒

dx

dy

=

(3x

2

+2x+1)

1

dx

d

(3x

2

+2x+1)

⇒

dx

dy

=

(3x

2

+2x+1)

1

(6x+2)

∴

dx

dy

=

(3x

2

+2x+1)

2(3x+1)