Math, asked by RJRishabh, 1 year ago

Differentiate

y =  \sqrt{1 + e {}^{x} }
with respect to x

Answers

Answered by Anonymous
3

GOOD \:  \: MORNING \:  \\  \\ y =  \sqrt{1 + e {}^{x} }  \\  \\ Differentiate \:  \: both \: sides \: w.r.t \: x \: w e \: have \\  \\ dy \div dx \:  = (1 \div 2 \sqrt{(1 + e {}^{x} )} ) \times e {}^{x}  \\  \\ dy \div dx \:  = e {}^{x}  \times (1 \div 2 \sqrt{(1 + e {}^{x}) }

Answered by TheLifeRacer
2

Hi

Solution :- y = (1 + e^x)^1/2

Diffrentiating (1 + e^x) with respect to x

y = (1+e^x)^1/2

y =

dy/dx = 1/2 {1 + e^x}^(1-1/2)* e^x

Note:- 1st of all we diffrenciat (1 + e^x)^½ function then diffrenciate ( 1+ e^x) functions of function

diffrentiation of (1 + e^x)^½ = 1/2( 1+ e^x) ^-½ then diffrenciate function of function (1+ e^x) = e^x

after substituting value we get .

dy/dx = 1/2( 1+ e^x)-½* ex

Answer

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Hope it helps you !!!

@Raj

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