Question

differentiate
$y = ( {x}^{3} + 4)sinx$

Answer 1

hey
here is ur answer
use uv rule
dy/dx. =(x^3+4)dsinx/dx+sinx d(x^3 +4)/dx
dy/dx=(x^3+4)cosx +sinx(3x^2)
I hope this will help
#Prem

Answer 2

hey here is your answer

I hope it will help you..