Differentiate the following √e^(3x+7) + 5
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Differentiation of a^x = (a^x)×(loga)
d(uv)/dx = [d(u)/dx]×v + [d(v)/dx]×u
Using chain rule :-
d(√e^(3x+7) + 5)/dx
= d[(√e^(3x+7)]/dx + 0
= d{e^[(1/2)(3x+7)]}
= e^[(1/2)(3x+7)]×loge×d[(1/2)(3x+7)]/dx
= e^[(1/2)(3x+7)]×1×(1/2)×3
= (3/2)√e^(3x+7)
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hope it helps
Step-by-step explanation:
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