Math, asked by jyotigaikwad7930, 4 months ago

Differentiate the following √e^(3x+7) + 5
plz answer this question it urgent..... ​


Anonymous: hi

Answers

Answered by Robonaut
2

Differentiation of a^x = (a^x)×(loga)

d(uv)/dx = [d(u)/dx]×v + [d(v)/dx]×u

Using chain rule :-

d(√e^(3x+7) + 5)/dx

= d[(√e^(3x+7)]/dx + 0

= d{e^[(1/2)(3x+7)]}

= e^[(1/2)(3x+7)]×loge×d[(1/2)(3x+7)]/dx

= e^[(1/2)(3x+7)]×1×(1/2)×3

= (3/2)√e^(3x+7)

:-)

Answered by diyasangwan02
3

Answer:

hope it helps

Step-by-step explanation:

If x=1−t1+t;y=2t1+t, then d2ydx2 = · 2. The derivative of tan−1(2x1−x2) with respect to cos−1√1−x2 is · 3. If √r=aeθcotα

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