Math, asked by funtriplifesss, 7 months ago

differentiate the following function ​

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Answered by adityajadhav192005
4

Problem decoded dude

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Answered by Anonymous
42

Your Question:

\tt \bf \blue Differentiate\:\: \dfrac{x^3\sin x}{\cos x}

Your Answer:

\tt \frac{\text{d}\dfrac{x^3\sin x}{\cos x}}{\text{d}y}\\\\ \tt \Rightarrow x^3.\sin x \frac{\text{d}\cos x}{\text{d}y}+\cos x.\frac{\text{d}x^3\sin x}{\text{d}y} \\\\ \tt \Rightarrow x^3.\sin x.(-\sin x) + \cos x[x^3.\frac{\text{d}\sin x}{\text{d}y}+\sin x\frac{\text{d}x^3}{\text{d}y}]\\\\ \tt  \Rightarrow x^3.\sin x.(-\sin x) + \cos x[x^3(\cos x)+\sin x.3x^2] \\\\ \tt \Rightarrow -x^3sin^2x + \cos x[ x^3\cos x + 3x^2\sin x] \\\\ \tt \Rightarrow -x^3sin^2x + x^3\cos^2x+3x^2\sin x.\cos x

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