Question

Differentiate the following function w.r.t.x:

Answer 1

this is your answer plz do verify

Answer 2

Solution:-

given by:-
$f(x) = y = 9 \sin(x) + \sin(3x) \\ diff \: with \: r \: to \: x \\ \frac{dy}{dx} = 9 \cos(x) + 3 \cos(x) \\ \frac{dy}{dx} = f( \frac{\pi}{3} ) = 9 \cos( \frac{3\pi}{3} ) + 3 \cos( \frac{3\pi}{3} ) \\ = 9 \times \frac{1}{2} - 3 \times \frac{1}{1} \\ = \frac{9}{2} - \frac{3}{1} \\ = \frac{9-6}{2} \\ = \frac{3}{2}$
☆i hope its help☆