differentiate the following function w. r. t. x:
(x2 - 4x + 5) (x² – 2).
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1
y=
x
2
+4x−7
[
x
=
2
x
1
Differentiating w.r.t. x, we get
dx
dy
=
2
x
2
+4x−7
1
⋅
dx
d
(x
2
+4x−7)
=
2
x
2
+4x−7
1
(
dx
d
x
3
+
dx
d
4x−
dx
d
7)
=
2
x
2
+4x−7
1
⋅(2x+1−0)
=
2
x
2
+4x−7
2(x+2)
=
x
2
+4x−7
(x+2)
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